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Co-Authored-By: 狸花猫/Claude-Qwen3.6-Plus 🐾
102 lines
2.4 KiB
TypeScript
102 lines
2.4 KiB
TypeScript
/**
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* @fileoverview 矩阵运算，本来是要引入 gl-matrix, 但是考虑到 g-mobile 对大小有限制，同时 g-webgl 使用的 matrix 不一致
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* 所以，这里仅实现 2D 几个运算，上层自己引入 gl-matrix
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* @author dxq613@gmail.com
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*/
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/**
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* 3阶矩阵相乘
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* @param {number[]} a 矩阵1
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* @param {number[]} b 矩阵2
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*/
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export function multiplyMatrix(a: number[], b: number[]) {
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const out = [];
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const a00 = a[0];
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const a01 = a[1];
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const a02 = a[2];
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const a10 = a[3];
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const a11 = a[4];
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const a12 = a[5];
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const a20 = a[6];
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const a21 = a[7];
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const a22 = a[8];
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const b00 = b[0];
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const b01 = b[1];
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const b02 = b[2];
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const b10 = b[3];
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const b11 = b[4];
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const b12 = b[5];
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const b20 = b[6];
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const b21 = b[7];
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const b22 = b[8];
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out[0] = b00 * a00 + b01 * a10 + b02 * a20;
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out[1] = b00 * a01 + b01 * a11 + b02 * a21;
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out[2] = b00 * a02 + b01 * a12 + b02 * a22;
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out[3] = b10 * a00 + b11 * a10 + b12 * a20;
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out[4] = b10 * a01 + b11 * a11 + b12 * a21;
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out[5] = b10 * a02 + b11 * a12 + b12 * a22;
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out[6] = b20 * a00 + b21 * a10 + b22 * a20;
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out[7] = b20 * a01 + b21 * a11 + b22 * a21;
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out[8] = b20 * a02 + b21 * a12 + b22 * a22;
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return out;
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}
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/**
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* 3阶矩阵同2阶向量相乘
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* @param {number[]} m 矩阵
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* @param {number[]} v 二阶向量
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*/
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export function multiplyVec2(m: number[], v: number[]) {
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const out = [];
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const x = v[0];
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const y = v[1];
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out[0] = m[0] * x + m[3] * y + m[6];
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out[1] = m[1] * x + m[4] * y + m[7];
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return out;
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}
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/**
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* 矩阵的逆
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* @param {number[]} a 矩阵
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*/
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export function invert(a: number[]) {
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const out = [];
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const a00 = a[0];
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const a01 = a[1];
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const a02 = a[2];
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const a10 = a[3];
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const a11 = a[4];
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const a12 = a[5];
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const a20 = a[6];
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const a21 = a[7];
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const a22 = a[8];
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const b01 = a22 * a11 - a12 * a21;
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const b11 = -a22 * a10 + a12 * a20;
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const b21 = a21 * a10 - a11 * a20;
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// Calculate the determinant
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let det = a00 * b01 + a01 * b11 + a02 * b21;
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if (!det) {
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return null;
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}
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det = 1.0 / det;
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out[0] = b01 * det;
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out[1] = (-a22 * a01 + a02 * a21) * det;
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out[2] = (a12 * a01 - a02 * a11) * det;
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out[3] = b11 * det;
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out[4] = (a22 * a00 - a02 * a20) * det;
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out[5] = (-a12 * a00 + a02 * a10) * det;
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out[6] = b21 * det;
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out[7] = (-a21 * a00 + a01 * a20) * det;
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out[8] = (a11 * a00 - a01 * a10) * det;
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return out;
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}
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